some one hewp plzzzzz Create a unique example of dividing a polynomial by a monomial and provide the simplified form. Explain, in complete sentences, the two ways used to simplify this expression and how you would check your quotient for accuracy.
thank you you were alot of help to me :)
Okay first we got to understand your problem: \(\text{Create a unique example of dividing a polynomial by a monomial and provide}\) \(\text{the simplified form. }\) So let's set some questions up: \(1) x^2 + 8x + 12 / x+ 2\) \(2)x - 2 +1/3x\) Okay for number one follow the steps below: 1) Factor out the numerator, so now you have \((x+2)(x+6).\) 2) Cancel out \((x+2)\) in the numerator and in the detonator. 3) Now you are left with the simplified answer, which is \(x+ 6\). Okay for number two follow the steps below: 1) Multiply \(x - 2 +1/3x\) by \(3x^2\) 2) You get \(3x^3 - 2x^2 + 3x^2/ 3x\) 3) That simplifies to x \(\text{Explain, in complete sentences, the two ways used to simplify this expression}\) \(\text{and how you would check your quotient for accuracy.}\) What I did: I simplified the expression. I explained how I simplified the expression. What you do: Check your quotient for accuracy. @mikala1 I believe you know how to do that? (If you don't I'll do it for you.)
I like the first one, but the second one is a little wrong. :-)
Tell me how to fix it. There's a medal in it for you ^_^.
Oh. Such a stupid mistake I made. Now I feel silly.
Another way:\[\begin{aligned}= & \dfrac{x -1}{3x} \\ \\ \\ = & \dfrac{x}{3x} - \dfrac{1}{3x} \\ \\ \\ = & \dfrac{1}{3} - \dfrac{1}{3x} \end{aligned}\]I did a mistake in the last post too :\
It's all good. Thank you Parth. I just don't know why I forgot such a vital step :| It's sleep deprivation. I've even answered History questions incorrectly :S
Nah, happens, like it happened to me above.
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