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Solve for x (x-2)^-4=625
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Do you know of x^-2 = 1/(x^2)?
no I think the answer is x=7 is that correct
\((x-2)^4 =\dfrac{1}{625}\) \(\sqrt[4]{(x-2)^4} = \sqrt[4]{\dfrac{1}{625}}\) \(|x-2| = \dfrac{1}{\sqrt[4]{625}} = \dfrac{1}{5}\) \(|x-2| = \dfrac{1}{5}\)
There are two answers.
x= 7 is not correct.
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Ok I have math processong errors when you gave me thAt first reply and how do you get two solutions
Look at last step. There is absolute value.
Do you know how to get rid of absolute value?
I can't see your last step because it all says math processing error
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So then does x=.5 and x=-2 is that what you are meaning what the answers are
Is that what you are meaing
Can someone tell me if x=-2 and x=.2 are the answers to this problem
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