Question

Can someone explain to me what exactly this problem means? I think I did it right, but I'm not sure.

Answer 1

I think it should be \[e^{-(x^2+y^2)}=e^{-2}\]

Answer 2

But is that enough?

Answer 3

It might be quite a bit simpler to write \(x^{2} + y^{2} = 2\)

Answer 4

taking logs of both sides, and multiplying by both sides by -1. I see... should I write it \[x^2+y^2-2 = z\] . Im having trouble with this 3D stuff...

Answer 5

So, I graphed both in wolfram alpha. When I graph mine, it gives a surface, when I graph what you wrote, it gives a circle. I assume that the circle is correct because it represents one contour, where a surface would be all possible contours... That sounds right? @tkhunny