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Verify the identity. sin (x + y) - sin (x - y) = 2 cos x sin y
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use Sum and Difference Identity : sin(x±y) = sinxcosy ± cosysinx
oh okay! thank you! give me a minute to see if I can get teh answer
\[2cosxsiny=sinxcosy+cosxsiny-sinxcosy+cosxsiny\] \[2cosxsiny=2cosxsiny\]
or you can also substitute sin(x±y) = sinxcosy ± cosysinx sin (x + y) - sin (x - y) = 2 cos x sin y (sin x cos y + cos y sin x) - (sin x cos y - cos y si nx) = (sin x cos y - sin x cos y + cos y sin x + cos y sin x) = ∴ 2 cos x sin y = 2 cos x sin y :-)
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