Question

Find the min y-value on the graph of y = f(x)
f(x)=x^2+8x-5

Answer 1

the formula for this is y= ax^2+bx+c , a = 0
x= -b/2a were b=-8 correct

Answer 2

x= -b/(2a)

x= -8/(2(1))

x = -4

now plug this into f(x)=x^2+8x-5 to find the min

Answer 3

i come up with (4)^2+8(-4)-5 which is 16-32-5 which come up to -21

Answer 4

good

Answer 5

thanks Mr Thompson i been trying to figure this one out for a while

Answer 6

np

Answer 7

It is nice to have people that can help