Question

integrate absolute value of (6-x) dx from 5 to 9 using midpoint riemann

Answer 1

\[\int\limits_{5}^{9}\left| 6-x \right|dx\]

Answer 2

So the first thing I did was I split up the integral to be this: \[\int\limits_{5}^{6}6-x dx + \int\limits_{6}^{9}-6+xdx\]

Answer 3

Is that the right first step?

Answer 4

The midpoint riemann sum formula is: \[\Delta x \Sigma f(a+(j-\frac{ 1 }{ 2 })\Delta x)\]

Answer 5

How many subintervals from 5 to 9?

Answer 6

4 subintervals.