using L’Hôpital’s Rule evaluate the limit
1)lim 1nx^2/x^2-1
x→1
2)lim e^x/2/x
x→ ∞

Question

using L’Hôpital’s Rule evaluate the limit
1)lim     1nx^2/x^2-1
   x→1
2)lim  e^x/2/x
x→ ∞

anonymous · Answer

@BenjaminEE

anonymous · Answer

In problem one. What is the first part?
1n x^2? Is that n * x^2?

anonymous · Answer

And the second one:
is it:
$$\frac{ e^{x/2} }{ x }$$

anonymous · Answer

and the other one is #36

anonymous · Answer

Aha sorry, one sec :)

anonymous · Answer

lol its okay (:

anonymous · Answer

Ok the first one:
(ln x^2) /  (x^2 -1 )
Derive both sides:
(1/x^2 * 2x) / (2x) = 1/x^2, 
input 1 into x and you'll get:
1/1^2 = 1

anonymous · Answer

And the second one:
e^(1/2 x) / x 
Derive both sides:
1/2 * e^(1/2 x) / 1
= e^(1/2 x) / 2
Now as x grows towards infinity so will e^(1/2 x) / 2 do
Which means that:
lim (x -> infinity) e^(1/2 x) / x = + infinity

anonymous · Answer

yay !i actually got the second part right

anonymous · Answer

thank you ! that helped alot :)