Question

using L’Hôpital’s Rule evaluate the limit
1)lim 1nx^2/x^2-1
x→1
2)lim e^x/2/x
x→
∞

Answer 1

@BenjaminEE

Answer 2

In problem one. What is the first part?
1n x^2? Is that n * x^2?

Answer 3

And the second one:
is it:
\[\frac{ e^{x/2} }{ x }\]

Answer 4

and the other one is #36

Answer 5

Aha sorry, one sec :)

Answer 6

lol its okay (:

Answer 7

Ok the first one:
(ln x^2) / (x^2 -1 )
Derive both sides:
(1/x^2 * 2x) / (2x) = 1/x^2,
input 1 into x and you'll get:
1/1^2 = 1

Answer 8

And the second one:
e^(1/2 x) / x
Derive both sides:
1/2 * e^(1/2 x) / 1
= e^(1/2 x) / 2
Now as x grows towards infinity so will e^(1/2 x) / 2 do
Which means that:
lim (x -> infinity) e^(1/2 x) / x = + infinity

Answer 9

yay !i actually got the second part right

Answer 10

thank you ! that helped alot :)