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Suppose that 55% of all adults regularly consume coffee, 45% regularly consume carbonated soda, and 70% regularly consume at least one of these two products. a) What is the probability that a randomly selected adult regularly consumes both coffee and soda? b. What is the probability that a randomly selected adult doesn’t regularly consume at least one of these two products?
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a) P(A N B) = P(A) + P(B) - P(AUB) = .3
for b. I'm stuck so far P(AUB)' but isnt that just 1-.7 ????
hey you got it....part b) is just 0.3 as well
I'll post one more that I was stuck on for a while
Ven diagrams can help with these type of problems
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How would I go about this one \[P(A_1' & A_2' U A_3)\]
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