Write a recursive formula for the sequence 7, 13, 19, 25, 31 then find the next term in the sequence?
13-7=6 19-13=6 hence x+6 hence 31+6
well, you know that \[a _{n}=a _{1}+(n-1)d\] you can find \[d=a _{2}-a _{1}\] you know, that \[a _{1}=7 \] \[a _{2}=13\] what is d?
is it: an = an– 1 + 6, where a1 = 7; 37?
I just wanted to make sure the answer I got was right. ^^;;
the answer should be \[a _{_{n}}=7+6n-6=1+6n\] when n is a number of member in sequance
no 7+(6-1)n 7+5n in this case n=6 7+30 37
for example, you need to find \[a _{6}=1+6*6=37\]
My answers have to look like this, that's what confused me. an = an– 1 + 6, where a1 = 7; 37 an = an– 1 + 6, where a1 = 37; 7 an = an– 1 – 6, where a1 = 6; –23 an = an– 1 – 6, where a1 = 7; –8
It's multiple choice. =/
The first answer is correct
That's what I figured, thanks
for multiple choice questions approach it in the simplest way possible which is the first one both the methods are correct
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