Question

Factor 5a3 + 15a2 – 6a – 18

Answer 1

I used to have problems with this kind of things, until it became clear that they are specially made to be factored ;)

Look at the first two terms: 5a²(a+3)

Second two terms: -6(a+3)

So: 5a²(a+3)-6(a+3)

Now you can do still one more step...

Answer 2

I mean: It is not just a random polynomial, but it is chosen in such a way that factoring is easily possible.

Answer 3

@zehanz
(5a2 – 3)(a + 6) is that right?

Answer 4

@ZeHanz wait no, its (5a2 – 6)(a + 3) right?

Answer 5

OK, now you are right!!

Answer 6

hahaha!!(: thank youu. so it is (5a2 – 6)(a + 3)?

Answer 7

Yup!