Question

Solving the flowing integral
sin^3xcos2xdx

Answer 1

\[\int\limits_{?}^{?} \sin^3xcos^2x dx\]

Answer 2

Use the fact that sin^2=1-cos^2 to get
sin^2xcos^x (1-cos^2x) and substitute u=cos x du=-sinx to get
-integral u^2(1-u^2)du.
you should be able to handle it from here

Answer 3

sin^2xcos^2x sorry