Question

Can someone help me simplify this radical expression, please?
√45n^5

Also can you tell me how you did it?

Answer 1

i take it is
\[\sqrt{45n^5}\] right?

Answer 2

first step is to factor \(45=9\times 5\) and this helps because you know what the square root of 9 is, namely 3
you can write
\[\sqrt{45n^5}=\sqrt{9\times 5\times n^4\times n}=\sqrt{9}\sqrt{n^4}\sqrt{5n}=3n^2\sqrt{5n}\]

Answer 3

we can take care of \(\sqrt{n^5}\) in your head
two goes in to 5 twice, with a remainder of 1, so \(n^2\) comes out of the radical and one \(n\) stays in, making \(\sqrt{n^5}=n^2\sqrt{n}\)

Answer 4

Okay hold on let me write this down

Answer 5

i don't understand

Answer 6

@satellite73 how did you get rid of the 5?

Answer 7

in the last step

Answer 8

He got rid of the 5 by putting 2 into 5 twice, and it had a remainder of 1, so it came out as n2

Answer 9

I still don't get it

Answer 10

can I plz get some help

Answer 11

LOL