I need to find the least common multiple of x^2-3x, x^2+3x, sorry can't write the problem right.. heh..
Welcome on the site. Do you know how to factor each of them?
look at what you can use to be able to multiply \[x(x-3)\] x^2 + 3 doesn't have a common multiple unless you want to start using imaginary
factored they are x(x-3) and x(x+3) not sure what to do from here
Now write dem unique factors down in both your polynomials.
I mean, take for example these two polynomials: \((x +1)(x - 3)\) and \((x + 3)(x + 1)\) The unique factors in both the polynomials are \(x + 1\), \(x - 3\) and \(x + 3\). Then multiply to get the lowest common multiple.
so in x(x+3) and x(x-3) the unique ones are (x-3) and (x+3) and multiply them? so x^2-9?
x^2 + 3 doesn't have a common multiple if you are talking about elementary algebra.
Brr, I read that as \(x^2 + 3x\) too. Silly me
imaginary is intermediate-level
oh lol!
in that case \[x(x+3)\]
I didn't know you can edit your question LOL
lolsorry about that
was that right? x^2-9?
x, x+3 and x-3. Multiply
yes if you have NO middle term, then you might be looking at + and -
x^2+3x(x-3)=x^3-3x+3x^2-9x= x^3+3x^2-12x?
right?
what exactly are you doing?
i don't even know anymore to be honest
\[x^3+3x^2-12 = x(x^2+3x-12)\]
ah i see..
thanks :)
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