Question

Find the equation of the circle with center at (3, 2) and through the point (5, 4).

Answer 1

since the center is (3,2)
so
(x-3)^2+(x-2)^2=r^2
agree?

Answer 2

sorry
is (x-3)^2+(y-2)^2=r^2

Answer 3

and (5,4) is on the circle , so put it into it
then you'll get r=\[2\sqrt{2}\]
so (x-3)^2+(y-2)^2=8

Answer 4

Thank You

Answer 5

welcome