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nP5 =42(nP3)
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56
can u clarify? and tell me the steps?
n P 5 = 42( n P 3 ) n*(n-1)*(n-2)*(n-3)*(n-4) = 42( n*(n-1)*(n-2) ) Let z = n*(n-1)*(n-2) which would give us z(n-3)*(n-4) = 42z (n-3)(n-4) = 42 n^2 - 7n + 12 = 42 n^2 - 7n + 12 - 42 = 0 n^2 - 7n - 30 = 0 (n - 10)(n + 3) = 0 n - 10 = 0 or n+3 = 0 n = 10 or n = -3 Since n > 0, this means that the only solution is n = 10
oh, this was a real question? lol i thought it look'd like something familiar. Lol
i saw this on the internet is this right? n!/(n - 5)! = 42 * n! / (n - 3)! (n - 3)(n - 4) = 42 n = 10
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yes that's correct (missing a few steps, but has the right idea and answer)
oh ok well thanks
np
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