Question

Explain what initial values y(a)=b would give a unique solution to the ODE ydydx=sec(x)

Answer 1

\[y\frac{\mathrm dy}{\mathrm dx}=\sec(x)\]

Answer 2

what do you get after you separate the variables and integrate?

Answer 3

I get y=+-sqrt(ln(sec(x)+tan(x))+C)