Question

Solve (2x-3y^4)^3 (x^3 + y)^0 divide (4xy-2)^3

Answer 1

so how would i do it?

Answer 2

@zepdrix can u help?

Answer 3

ok

Answer 4

so will it be (2x - 3y^4)3 over (4xy - 2)^3 ?

Answer 5

\[\large \frac{(2x-3y^4)^3(x^3+y)^0}{(4xy-2)^3}\]So you simplified it to\[\large \frac{(2x-3y^4)^3}{(4xy-2)^3}\]
Yah looks good so far. hmm

Answer 6

okay thanks :)

Answer 7

yea i got it thanks