Question

Log4 (x+1) + log4 (x-3) = log4 12 solve for x

Answer 1

use the property of Log
\[\Large \log_b M+\log_b N = \log_b {MN}\]

Answer 2

I don't know what to do with that

Answer 3

your b =4 , M = (x+1), N = (x-3)

Answer 4

\[ \Large{\log_b(M) \quad\;\;\;\; + \log_b(N)\quad \quad\quad=\log_b(MN)\\\log_4(x+1) + \log_4(x-3)}\;\;\;\;= \]

Answer 5

Then what?

Answer 6

what do you have so far?

Answer 7

The same equation

Answer 8

log4[(x+1)(x-3) = log4 12

Answer 9

Do you distribute?

Answer 10

FOIL (x+1)(x-3)

Answer 11

What happens next?