Question

Write a system of equations to solve the following problem. Let c be the number of child tickets and a be the number of adult tickets.



Each child ticket for a ride costs $3, while each adult ticket costs $5. If the ride collected a total of $115, and 33 tickets were sold, how many of each type of ticket were sold?


A. 3c + 5a = 115
a + c = 33

B. 5c + 3a = 115
c + a = 33

C. 3c + 5a = 33
a + c = 115

D. 3a + 5c = 33
a + c = 115

Answer 1

i would go with the first one

Answer 2

others are silly

Answer 3

if each child's ticket is $3 and there are 4 child tickets sold, then the total is \(3\times 4\)
if each child ticket is $3 and there are "c" child tickets sold, the total is \(3c\) for the childs tickets

Answer 4

similarly \(5a\) for the adult tickets, for a total of \(3c+5a\) which you know is $115

Answer 5

let "a" be the amount of adult tickets sold
let "c" be teh amount of children tickets sold

if the total amount of tickets sold is 33
that would mean
a+c= 33

now a adult ticket cost $5
and a children ticket costs $3

so the total cost of all the children tickets sold would be 3c
whereas the total cost of the adult tickets sold would be 5a

if a total of $115 was collected, that would mean
5a+3c=115

i am disappointed at you satellite

Answer 6

oh wait nvm you did explain it