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***Fan and Medal award*** \[find the derivative of the function f(x)=\frac{ e ^{-2t} }{ 1+4t }\]
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looks like quotient rule and chain rule.
\[u=e^{-2t},\ v=1+4t\]\[du=-2e^{-2t},\ dv=4\]\[(vdu-udv)/v^2\]
\[\frac{ (1+4t)*2e ^{-2t}-e ^{-2t}*4 }{( 1+4t) ^{2}}\]
@stamp \[\frac{ (1+4t)*2e ^{-2t}-e ^{-2t}*4 }{( 1+4t) ^{2}}\]
@oheneba Simplify your numerator.
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