Use the angle difference identities to find the exact value of the trigonometric expression. cos 195° can someone tell me the answer pleasee?
this is what the question is asking you to do, to use the cos of the diffrence of angles...
i'm sorry i dont understand?
Use A=240 B=45
okay thank you :) one second.
Use this \[\cos (A-B)=\cos A \times \cos B+\sin A \times \sin B\]
how do i get sin A and sin B?
just sub the values that @ash produces
this is the formula for cos(A-B)
do you want a proof for that formula...
\[\sin 240=\sin (180+60)=-\sin 60\]
i get 195 when i do Cos(A-B)
Yes, but you need to find the value of \(\cos 195\) So we use \[\cos (A-B)\] and then we expand it to find the value of cos 195
240-45
im not following. i did (240 -45) and got 195
i don't understand what i'm supposed to do , this is supposed to be an Algebra II course but its trig problems i dont even know what cos and sin is.
You haven't studied trigonometry, have you?
not at all.
Oh, then how would you know this? Was this part of your course?
yes , this is my last course before i graduate and it says nothing about any of this in my textbooks so im at a loss.
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