find the trig value below without a calculator. sec theta=7/4, find cos theta+cos theta tan^2 theta
\[\sec \theta=\frac{ 7 }{ 4 }, \cos \theta +\cos \theta \tan ^{2} \theta\]
okay I know that sec theta=sec(- theta)
I also know that sec= 1/cos
but i cant put it together.
any luck @NoelGreco ?
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@natnatwebb cos theta+cos theta tan^2 theta Factor out cos(theta) to get cos(theta)[ 1 + tan^2 (theta)]=
[1 + tan^2 (theta)]= is a trig identity. Look it up if you don't remember it at the moment.
You'll also need the identity cos(theta) = 1/sec(theta) and this answer will fall right out.
okay, every single question i did by myself this afternoon i got wrong.
okay...lemme think.
Just take one question at the time.
okay, how did you factor out the cos?
and and...the 1, where did that sucker come from
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