Finding the Limit
Lim (x^2)-2x+3/(3x^2)+2x-5
x-2

Question

Finding the Limit
Lim   (x^2)-2x+3/(3x^2)+2x-5
x->2

anonymous · Answer

$$\lim_{x \rightarrow 2} x ^{2}-2x+3/3x^{2}+2x-5$$

anonymous · Answer

do you get $\frac{0}{0}$ if you substitute?

anonymous · Answer

if not, then whatever you get is the answer

tkhunny · Answer

Since what you have written is continuous at x = 2, it is simple: 4 - 4 + 1/4 + 4 - 5 = -3/4.

Of course, if you meant $\dfrac{x^{2} - 2x + 3}{3x^{2} + 2x - 5}$, that would give a different result.

anonymous · Answer

unless you get $\frac{0}{a}$ and $a\neq 0$ in which case there is no limit

anonymous · Answer

tkhunny, I meant the second problem you put

anonymous · Answer

a quick calculation gives $\frac{3}{11}$ but you should check my arithmetic

tkhunny · Answer

@maink2 Well, then you should WRITE that.  Please look at what you have written and take some good, careful time to reflect on the Order of Operations.

anonymous · Answer

That's what I got as well satellite73. Didn't know if there was more to it though