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Domain and Range f(x)= √3x+2
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\[ {x \in \mathbb{R} : x \ge 0 }\]
Domain^
\[f \in \mathbb{R} : f \ge 2\]
range ^
then again maybe it is \[f(x)=\sqrt{3x+2}\]
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i should of put parenthesis around it huh? XD
@satellite73 your right
@zepdrix :D
yeah true I did the domain & range based on: \[f(x) = \sqrt(3 x)+2\]
sorry about that :X
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@zepdrix help lol wth...
i know how to get Domain by setting the equation >_ to zero then solve. But how do you get the Range?
\[3x+2\geq =\iff 3x\geq -2\iff x\geq-\frac{2}{3}\]
for the domain
range is \([0,\infty)\) since the square root means the positive square root
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always ?
and 0 is included?
yes, \(\sqrt{x}\geq 0\) always
zeros is included because the square root of zero is zero
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