What ion does an Oxygen atom form? Why? Draw in the electrons for the deionized and ionized Oxygen atom. Find the Nuclide symbol for both. I have the answers: Deionized has 6 valence electrons and ionized has 2 valence electrons, nuclide symbol differs by 2 electrons. Can someone explain why? And draw out the little bohr models for both examples? Thanks!
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example of the blank bohr models
wrong. neutral atom has 6 valence electrons. to become an ion and get a stable electronic configuration, oxygen atom takes in 2 electrons to become and 02- ion. It has 6 + 2 = 8 valence electrons now
That's the answer our teacher gave her four classes of 600 students each, should I tell her that she's wrong?
well. if she said (as what you typed) that an oxygen ion has 2 valance electrons, she is definitely wrong
maybe she meant valence electron shells?
as a general guideline, hydrogen and helium (period 1 elements) needs 2 valance electrons to be stable. then, up to period 3, they need 8 valence electrons to be stable
after period 3, it gets quite complicated since Bohr's model is wrong/innacurate
i'll just show you how to draw the models
ok, thanks! haha I'll ask her about it tomorrow
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