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PLEASE HELP. Consider the following reaction: P2O5(s)+3H2O(l)<--->2H3PO4(aq) a. Write the expression for Kc for the reaction. For this I got: Kc=[H3PO4]^2/[P2O5]*[H2O]^3 b. If the value of Kc is 13.27 calculate the concentration of H3PO4 that will be present at equilibrium. I have no idea how to do b... I think I need at least an initial concentration or a concentration at equilibrium but the problem does not give any. Is there any way to solve this??? Thanks.
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liquid and solids dont have concentrations
hence the Kc is as good as the concentration of the aqueous solution of H3PO4
Soo... the concentration of H3PO4 is sqrt(13.27)?
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