3x - 5y + z = 12 x + 6y - z = -4 2x - 5y - 2z = -8
@phi
i have a few others also
use elimination
can you get me started
are you finding the value of x,y and z?? just use elimination method
it might be easiest to change the order of the equations to x + 6y - z = -4 3x - 5y + z = 12 2x - 5y - 2z = -8
If you were to use the substitution method to solve the following system, choose the new system of equations that would result if x was isolated in the second equation.
the equation 1 and 2.first cancel out the z ..
you have to use sub
if we ignore the variables (but keep the same order) 1 6 -1 -4 3 -5 1 12 2 -5 -2 -8
ok
then what
the first step is to make the first column below the 1 all zeros multiply the first row by -3 and add that to the 2nd row
in other words, multiply -3 * 1 6 -1 -4 to get -3 -18 +3 +12 add those numbers to the 2nd row to get a new 2nd row
these are the options a. 4x + y = 8 -17y = 0 b. 2x - 11y = 16 4x + 7y = -16 c. -23y + 4z = 24 -17y = 0 d. 13y - 2z = 24 7y - 4z = 0
unless you are Rainmain, you have to go through the steps one by one
haha ok
o-13+4+24
or is it 6-13+4+24
phi you there
First, I am not sure where you got your numbers.
i added both sides together
2nd, looking at the "answers", I don't know what the question is ?
If you were to use the substitution method to solve the following system, choose the new system of equations that would result if x was isolated in the second equation. 3x - 5y + z = 12 x + 6y - z = -4 2x - 5y - 2z = -8
In that case, we are not solving for x,y,z . And they tell us to use substitution (which is a lousy way to solve for more than 2 variables... it is too confusing). But we have to use substitution.
if x was isolated in the second equation. that means "solve for x" in the equation x + 6y - z = -4 can you do that ?
yes one second
x=-4+z-6y
next, replace x with -4 + z -6y in the first equation and the 3rd equation first one: 3x - 5y + z = 12 replace x with (-4 + z -6y) 3(-4 + z -6y) - 5y + z = 12 distribute the 3 and get -12 +3z -18y -5y +z =12 can you simplify this ?
ya one sec
\[-12+4z-13y=12\]
I would move the -12 to the other side
oh ok
and write the terms alphabetical just so it is easier to match things up
ok
so \[-13y+4z=24\]
and double check your arithmetic on the y term
13y not -13y
?
3x - 5y + z = 12 replace x with (-4 + z -6y) 3(-4 + z -6y) - 5y + z = 12 -12 +3z -18y -5y +z =12
collect terms: -18y -5y +3z + z = 12+12 if you factor out y and z you get: (-18-5)y + (3+1)z = 24
-18 + -5 = ?
-23
-23y+4z=24
yes. Be careful with the arithmetic or you'll never get the correct answer, even though you understand the algebra.
now see if any of the choices has that equation.
ok i got the answer
can you help me with another
If more than one answer had that, we would do the 3rd equation. The 3rd equation turns into -17y=0 (or 17y=0 , or y=0)
ok
heres another
If you were to use the elimination method to solve the following system, choose the new system of equations that would result after the variable z is eliminated in the second and third equations, then the first and second equations. 5x + 2y + z = -2 3x + 4y + 3z = 2 -4x - 3y - 3z = 1
please post it as a separate question
ok
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