n^2 - 49 = 0

Question

n^2 - 49 = 0

anonymous · Answer

n=7 nd n=-7

parthkohli · Answer

Hint: consider $(-7)^2 - 49$ and $7^2 - 49$

anonymous · Answer

Thats what i thought too, but my only choices are a)-7 b)7 c)=7 d) no soultion? so which one.

zehanz · Answer

Consider n²=49. YOu always end up with two possibilities (-7 and 7). 
Does n have to be a positive number, maybe?

anonymous · Answer

Well i dont know what too do at all. and those our my choices, and thats my wuestion so can someone just tel me the answer? please.

zehanz · Answer

Several people gave you the answer. If solving n²-49=0 is all you have to do, then n=7 or n=-7.
Sometimes, even books or tests are wrong...

anonymous · Answer

n^2 = 49 in finding n you just need to find the square root of 49

anonymous · Answer

i know the square root of 49 is 7. but is is -7 or just a regular 7.

zehanz · Answer

The solutions of n²-49=0 are:$$n=\pm \sqrt{49} = \pm 7$$

anonymous · Answer

we will consider it as + or - because sometimes it will become $$\pm \sqrt{49}$$

anonymous · Answer

@tommy12345 did u get it?

anonymous · Answer

Thank you, for all your help. sorry for being kinda rude, its just this is super confusing too me when ive learned none of it yet

anonymous · Answer

@ jedi17 yes thank you (:

zehanz · Answer

The only reason that there are two solutions is that when you replace n by 7 or by -7 in both cases the outcome is true: 
(-7)² - 49 = 0 - OK.
7² - 49 = 0 - OK.

anonymous · Answer

thanks.

zehanz · Answer

YW!

anonymous · Answer

its okay.. :)
that's good u'r welcome..

anonymous · Answer

(: