Mathematics
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OpenStudy (anonymous):
Use the definition of the derivative( see attachment) to find f ’(c) where fx = x^2 - 3x + 2 at c = 1
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OpenStudy (anonymous):
OpenStudy (anonymous):
@mathsmind can u help?
OpenStudy (anonymous):
yes i will be with u shortly after my phone call
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
ok
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OpenStudy (anonymous):
so how would i apply it?
OpenStudy (anonymous):
i will show u
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
\[f(x) = x^2-3x+2\]
OpenStudy (anonymous):
a=1, b=-3, and d= 2, c=1
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OpenStudy (anonymous):
okay
OpenStudy (anonymous):
let me plug them in
OpenStudy (anonymous):
okay
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
2x-3
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OpenStudy (anonymous):
okay i forgot to post the multiple choices here they are
A. -1
B. 1
C. 1/2
D. 2
OpenStudy (anonymous):
okay so i'll solve 2x - 3 right?
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
sorry i am on the phone at work
OpenStudy (anonymous):
ok
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OpenStudy (anonymous):
i will be with u in a moment
OpenStudy (anonymous):
-1 would be the ans though...
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
by the way keep h->0
OpenStudy (anonymous):
not h->c
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OpenStudy (anonymous):
i will do it again
OpenStudy (anonymous):
\[\lim_{h \rightarrow 0}\frac{(x+h)^2-3(x+h)+2-x^2+3x-2}{h}\]
OpenStudy (anonymous):
\[\lim_{h \rightarrow 0}\frac{x^2+2hx+h^2-3x-3h+2-x^2+3x-2}{h}\]
OpenStudy (anonymous):
\[\lim_{h \rightarrow 0}\frac{2hx+h^2-3h}{h}\]
OpenStudy (anonymous):
\[\lim_{h \rightarrow 0}{2x+h-3}\]
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OpenStudy (anonymous):
\[f'(x)=2x-3\]
OpenStudy (anonymous):
\[f'(c)=2c-3\] and c =1 yeilds
\[f'(1)=2(1)-3=-1\]
OpenStudy (anonymous):
this is a better way to solve the problem than the ones i deleted, hope this helps and all the best
OpenStudy (anonymous):
are you following please use the new detailed steps in your answer
OpenStudy (anonymous):
ok