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Mathematics 14 Online
OpenStudy (anonymous):

Use the definition of the derivative( see attachment) to find f ’(c) where fx = x^2 - 3x + 2 at c = 1

OpenStudy (anonymous):

OpenStudy (anonymous):

@mathsmind can u help?

OpenStudy (anonymous):

yes i will be with u shortly after my phone call

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

so how would i apply it?

OpenStudy (anonymous):

i will show u

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

\[f(x) = x^2-3x+2\]

OpenStudy (anonymous):

a=1, b=-3, and d= 2, c=1

OpenStudy (anonymous):

okay

OpenStudy (anonymous):

let me plug them in

OpenStudy (anonymous):

okay

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

2x-3

OpenStudy (anonymous):

okay i forgot to post the multiple choices here they are A. -1 B. 1 C. 1/2 D. 2

OpenStudy (anonymous):

okay so i'll solve 2x - 3 right?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

sorry i am on the phone at work

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

i will be with u in a moment

OpenStudy (anonymous):

-1 would be the ans though...

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

by the way keep h->0

OpenStudy (anonymous):

not h->c

OpenStudy (anonymous):

i will do it again

OpenStudy (anonymous):

\[\lim_{h \rightarrow 0}\frac{(x+h)^2-3(x+h)+2-x^2+3x-2}{h}\]

OpenStudy (anonymous):

\[\lim_{h \rightarrow 0}\frac{x^2+2hx+h^2-3x-3h+2-x^2+3x-2}{h}\]

OpenStudy (anonymous):

\[\lim_{h \rightarrow 0}\frac{2hx+h^2-3h}{h}\]

OpenStudy (anonymous):

\[\lim_{h \rightarrow 0}{2x+h-3}\]

OpenStudy (anonymous):

\[f'(x)=2x-3\]

OpenStudy (anonymous):

\[f'(c)=2c-3\] and c =1 yeilds \[f'(1)=2(1)-3=-1\]

OpenStudy (anonymous):

this is a better way to solve the problem than the ones i deleted, hope this helps and all the best

OpenStudy (anonymous):

are you following please use the new detailed steps in your answer

OpenStudy (anonymous):

ok

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