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Mathematics 21 Online
OpenStudy (anonymous):

Trigonometry help? Has to do with unit circles.

OpenStudy (anonymous):

OpenStudy (anonymous):

\[\theta=\pi/6\]

OpenStudy (anonymous):

sorry, \[\theta=\pi/3\]

OpenStudy (anonymous):

how did you get that answer?

OpenStudy (anonymous):

tan=sin/cos, at \[\pi/3\] \[(\frac{ 1 }{ 2 },\frac{ \sqrt{3} }{ 2 })\] (cos, sin)

OpenStudy (anonymous):

\[\frac{ \frac{ \sqrt{3} }{ 2 } }{ \frac{ 1 }{ 2 } }=\sqrt{3}\]

OpenStudy (anonymous):

alternately, \[\tan^{-1} (\sqrt{3})\]

OpenStudy (anonymous):

ahh so it hits the point on a 30-60-90 triangle

OpenStudy (anonymous):

right, drop a vertical perpendicular line from the end point to the x axis

OpenStudy (anonymous):

|dw:1361902605164:dw| would look something like this?

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