Question

Find the number of possible 5-card hands that contain the cards specified. These cards are taken from a standard 52-card deck:

At most 1 ace

Answer 1

that doesn't really answer my question..

Answer 2

gee thanks

Answer 3

dude go away

Answer 4

anyway, the question is to find the number of 5-card hands that contain at most, 1 ace

Answer 5

either the 5-card hand has
(a) exactly one ace (how many possibilities), or
(b) no ace at all (how many possibilites)

add the results you get in (a) and (b)

Answer 6

?

Answer 7

So

Answer 8

help :(

Answer 9

X=3
2y+x=3

Answer 10

-.-

Answer 11

Is substitution

Answer 12

cool

Answer 13

Can you answer it

Answer 14

(a) has exactly one ace

choose one among 4 aces. That's 4C1
choose 4 cards that are not an ace. That's 48C4

by multiplication principle, the answer in (a) is \[ 4C1\times 48C4\]

Answer 15

that doesn't give me the right answer

Answer 16

that's only for (a)
you also have to compute (b), then add the two answers to get the desired answer.

Answer 17

and how is (b) done ?

Answer 18

How many cards aren't aces? Choose 5 from that.

Answer 19

48

Answer 20

choose 5 among 48, and that would be...?

Answer 21

I don't know I'm so confused..

Answer 22

check ^ my solution in (a). i know you can find the correct answer in (b)

Answer 23

...