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Find the derivative with respect to x of the given combination value of x √f(x)+g(x), x =3 I know d(√g(x)) = u /( 2√u ) and g(x) + f(x) = g(x+f(x)) * x' + f'(x) For this particular problem I tried to use both but I'm can't figure out how the answer ended up with a 15 on the numerator.
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\[\sqrt{f(x)+g(x)}\] u = f(x) + g(x) du = f'(x) + g'(x) \[d\sqrt u=\frac{1}{2\sqrt u}du\]\[=\frac{f'+g'}{2\sqrt{f+g}}\]
= (8 + 7) / 2sqrt(1 + 4) = 15 / 2sqrt(5)
Awesome! That makes this much more easier! Thank you so much!
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