Question

According to the rational root theorem, which is not a possible rational root of x^3 + 8x^2 - x - 6 = 0?
1
4
2
6

Answer 1

The possible rational roots are the factors of the constant term divided by the factors of the coefficient of the leading term.

Answer 2

The constant term is -6
The leading term is x^3 and its coefficient is 1

Answer 3

So the possible rational roots are the factors of -6 divided by the factors of 1

Answer 4

So what are the possible rational roots?

Answer 5

6

Answer 6

What are the factors of -6?

Answer 7

no clue???

Answer 8

Let me give you an example: The factors of 12 are 4 and 3 because 4 x 3 = 12

Answer 9

Also 2 and 6 are factors of 12 because 2 x 6 = 12

Answer 10

Also -1 and -12 are factors of 12 because -1 x -12 = 12

Answer 11

Now you tell me some factors of -6

Answer 12

what two numbers when multiplied equal 6

Answer 13

-6

Answer 14

1

Answer 15

ok. Now gojani91 wants to help you.

Good bye

Answer 16

lol ok then

Answer 17

damn you dont have to be rude mertsj

Answer 18

lol its fine dont worry about it :)

Answer 19

forget it, it's cool ill figure it out but thanks for trying to help i can be quite difficult...

Answer 20

what are the factors of -6

Answer 21

-1 x 6
1 x -6
2 x -3
3 x -2

Answer 22

1?

Answer 23

and 2

Answer 24

-3 am i right?

Answer 25

yes those are all roots

Answer 26

k so which do I choose from 1 and 2?

Answer 27

this is an easy problem because the leading coefficient is 1 from x^3 so all those numbers can be divided by 1

Answer 28

your question ask which is not a possible root number

Answer 29

oh ok so 4

Answer 30

so what numbers is not a factor of 6

Answer 31

yes you got it

Answer 32

thank you so much really appreciate it :)

Answer 33

no problem