Question

I could really use some help with these.. Please help me! Will give medal!!

Answer 1

do you need to find the other sides?

Answer 2

yes

Answer 3

@harsimran_hs4

Answer 4

cos 60 = sqrt(3)/ b
1/2 = sqrt(3)/ b
you can find b

then use tan 30 to find a

Answer 5

@harsimran_hs4 can you show me how to do it?

Answer 6

b = 2*sqrt(3)

tan 30 = sqrt(3)/a

1/sqrt(3) = sqrt(3)/a
a = sqrt(3) * sqrt(3)
a = 3

\[a = 3 \] \[b = 2\sqrt{3}\]

Answer 7

clear??

Answer 8

yes very thank you!

Answer 9

:)

Answer 10

:)

Answer 11

@harsimran_hs4 how about this one?

Answer 12

try it the same way taking sin and tan of angles and post your attempt

Answer 13

@harsimran_hs4

Answer 14

tan 45= 6/b
1=6/b
b=6
same for A?

Answer 15

for b calculation is right
use either Pythagoras for a because it`s rt angled triangle
or simply use sin or cos of any angle to get a