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Precalculus
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(-x^3+ 3x^2+ 3)+(3x^2+ x+4)
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-x^3 + 6x^2 + 7
group the same kinds.. the coefficient just tells you how much of the term you have
i agree
ingenuus's answer is correct, but (no offense to ingenuus) the explanation is a bit lacking. You can solve this problem fairly easily. You do it by looking at like terms. Like terms always have the same varible and exponent. For instance, 3x^2 and x^2 are like terms, but 3x and 3y are not. You divide the question into it's like terms, so (-x^3), (3x^2+3x^2) and (3+4). Then, you simply add like terms to get (-3x^3+6x^2+7).
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