What is the factored form of x^2 + 6x + 8? (x + 5)(x + 3) (x + 4)(x + 2) I think it is this one atm can you check (x + 7)(x + 1) (x + 3)(x + 3)
is this a homework problem?? somebody asked the same question
yes it is but i am wanting to see if i got it right
yes you got it right
thanks
what about this one What is the factored form of x2 – 7x + 12? (1 point) (x – 5)(x – 3) I think this is it (x – 6)(x – 1) (x – 5)(x – 2) (x – 4)(x – 3)
(x-5)(x-3) = x(x-3) -5(x-3) = x^2 -3x -5x +15 = x^2-8x +15 how can this be equal to x^2-7x+12?
i gave you the principle. try to figure out the pattern in it for every the equation of form(x+a)(x+b)
sorry have not done this before so i am trying to figure it out
remeber that x is real number even though it looks very complicated.. so it has all the property of real number and that means you can do the same operations for it as you do to the real numbers
expand (x+a)(x+b) and you will see what i mean
can you give me a hint so i can try to get it
well do you see this? (2+3)(4+6)=(2+3)*4 + (2+3)*6 =2*4+3*4 +2*6+3*6
i am confused
well do you see this? 2*(3+4)=2*3+2*4
what you mean
let's just use this equation.. 5(4+6)=5*4+5*6
i am asking that you know that operation that the equation above holds
i said i don't understand
if you don't understand this 5(4+6)=5*4+5*6, you don't understand your problem
i know that is why i asked for you to help
well ok. memorize this a(b+c)=ab+ac
ok
it means when you add b &c and multiply it by a, you get the same results as a times b plus a times c
a, b, c above are real numbers.. like 1, 2, 3, 4, 1/2, 1/3 .... stuffs
ok
so let's accept that this rule works and comeback to our problem (x+a)(x+b) first of all (x+a) is real number right? so by our rule, (x+a)(x+b)=(x+a)x+(x+a)b again, (x+a)x+(x+a)b=xx+ax+xb+ab =x^2+ax+bx+ab =x^2+(a+b)x+ab
i only used the a(b+c)=ab+ac rule.. try to follow it.
ok
so it says, (x+a)(x+b) equals x^2+(a+b)x+ab
would it be C then??
no no i only used a(b+c)=ab+ac to show you the pattern
the a, b used in (x+a)(x+b) are not same as the a(b+c) ...
it just means random number
every number
ugh i am confused
ok just for get about every thing and remember a(b+c)=ab+ac
insert a=(x+p) , b=x , c=q in that a(b+c)=ab+ac would you do that?
what does it tell you
i can't think straight my mind is messed up now i think i fixed to many computers that i can't think right
i am just asking you to plug (x+p), x, q into the a,b,c position is the equation a(b+c)=ab+ac this is just matching the same picture business
just plug it in!!!
i can't i am not able to think right
ok rest for while. the answer is (x+p)(x+q)=(x+p)x+qx anyways
i am going my head hurts
Join our real-time social learning platform and learn together with your friends!