Ask
your own question, for FREE!
Mathematics
12 Online
OpenStudy (anonymous):
Find the derivative with and without using the chain rule. f(x) = (x^3 - 1)^2
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
Do you know how to expand it? \[
(x^3-1)^2 = (x^3-1)(x^3-1)
\]
OpenStudy (anonymous):
no
OpenStudy (anonymous):
is that with the chain rule or?
OpenStudy (anonymous):
This is what is called "multiplication"
OpenStudy (anonymous):
ok
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
you factor it right?
OpenStudy (anonymous):
let me try to expand it
OpenStudy (anonymous):
Now we will use distributive property of multiplication. \[
(x^3-1)(x^3-1) = x^3(x^3-1)-1(x^3-1)=x^6-x^3-x^2+1=x^6-2x^3+1
\]
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
Now take the derivative.
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
ok hold on
OpenStudy (anonymous):
the derivative of x^6 - 2x^3 + 1 right?
OpenStudy (anonymous):
Yeah.
OpenStudy (anonymous):
i got 6x^2 (x^3 - 1)
OpenStudy (anonymous):
What is the derivative of \(x^6\)?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
What is the derivative of \(-2x^3\)?
OpenStudy (anonymous):
its 6x^5
OpenStudy (anonymous):
and -6x^2 for -2x^3
OpenStudy (anonymous):
so it will be 6x^5 - 6x^2 ?
OpenStudy (anonymous):
Yeah. You don't need to factor it.
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
so that's it?
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
okay can did we use the chain rule on this one or? no chain rule?
OpenStudy (anonymous):
are u there?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
@wio ?
OpenStudy (sirm3d):
chain rule was not used
OpenStudy (anonymous):
okay thanks
Can't find your answer?
Make a FREE account and ask your own questions, OR help others and earn volunteer hours!
Join our real-time social learning platform and learn together with your friends!