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64x^3-1=0
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Add 1 to the other side. Then divide 64 to the other side. this equals x^3=1/64
Then cube root each side. \[\sqrt[3]{x ^{3}} = \sqrt[3]{\frac{ 1 }{ 64 }}\]
then think 1x1x1=1^3 so you can cube root 1 for the numerator then for cube root of 64 = 4x4x4 = 4^3 so you get 4 in the denominator
so, you can conclude x=1/4
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