Question

I need help with an exam review question.. how do you write an equation for the line that is parallel to the given line and that passes through the given point? y=-5x+3; (-6,3)

Answer 1

well when u have two line in parallel then m1=m2

Answer 2

so in ur case the m1=m2=-5, and because the line is passing through the point (-6,3). then that yields to applying the following
\[\frac{y-y_1}{x-x_1}=m\]

Answer 3

sorry y1=5, x1=-6 and m=-5

Answer 4

\[\frac{y-(6)}{x-(-3)}=-5\]

Answer 5

do u know how to simplify this expression in the form y =mx+c

Answer 6

no haha

Answer 7

ok not to worry

Answer 8

\[y-6=-5(x+3)\]

Answer 9

oh wait .. so y=-5x+ ? idk

Answer 10

oh thx

Answer 11

you're more than welcome all the best

Answer 12

so I solve that?

Answer 13

y-6=-5x-15

Answer 14

y=-5x-9

Answer 15

which is parallel to y=-5x+3

Answer 16

thank you! this helps alot

Answer 17

all the best...