There are 6 orange, 2 red, 3 white, and 4 green candies in a box. Joe chooses a candy, looks at it,replaces it, and then draws another. What is the probability of him drawing 2 orange candies?
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OpenStudy (anonymous):
@pooja195
pooja195 (pooja195):
6/16
add allup then put the amount of candy there is
OpenStudy (helpsos):
nvm
OpenStudy (openstudier):
Since we are replacing, these are independent events (the probability of the first event doesn't affect the second event), so the formula is:
\[P(A and B)=P(A) * P(B)\]
OpenStudy (helpsos):
sorry :(
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OpenStudy (anonymous):
I believe it's \(\left(\dfrac{6}{16}\right)^2\)
OpenStudy (anonymous):
Hmmmmm.
OpenStudy (anonymous):
Yup, @OpenStudier is right.
OpenStudy (openstudier):
So what would be the P(A) and P(B)?
pooja195 (pooja195):
6/16 is the answer @OpenStudier
yr just explaing it too much
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OpenStudy (anonymous):
Oh, ok.
OpenStudy (openstudier):
@pooja195, one does not simply not explain on OpenStudy if @help123please doesn't understand. And also, you are wrong.
OpenStudy (anonymous):
Really?
OpenStudy (anonymous):
Yeah.
OpenStudy (anonymous):
And yes, I don't understand still.
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OpenStudy (openstudier):
Yes. What is the probability of drawing one orange?
OpenStudy (anonymous):
omg. typo
OpenStudy (anonymous):
there are 2 red candies
OpenStudy (anonymous):
sorry bout that :/
OpenStudy (openstudier):
So what is the probability of getting one orange?
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OpenStudy (anonymous):
One orange? 1/ 15?
OpenStudy (openstudier):
No. If there is 6 oranges from the total, one orange is 6/15=2/5
OpenStudy (anonymous):
Ohhh. Sorry bout that.
OpenStudy (anonymous):
Okay. But it is asking for 2 oranges.
OpenStudy (anonymous):
2/5*2?
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OpenStudy (anonymous):
[which is 8/10?]
OpenStudy (openstudier):
So if we know the probability of getting one orange, what is the proabability of getting two oranges twice in a row (what the problem is asking)?
OpenStudy (anonymous):
Is that right? 8/10?
OpenStudy (openstudier):
No, look back up at my earlier explanation.
OpenStudy (anonymous):
Oh. Okay...Lets see.
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OpenStudy (anonymous):
What is A and B?
OpenStudy (anonymous):
What do they represent?
OpenStudy (anonymous):
@Kitt020912
OpenStudy (openstudier):
A and B is what I refered to the probability of events A and B.
OpenStudy (anonymous):
Okay.
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OpenStudy (openstudier):
So the answer would be:
(2/5) x (2/5)... Understand?
OpenStudy (anonymous):
yes.
OpenStudy (anonymous):
Thanks.
OpenStudy (anonymous):
Que pensez-vous, Kitt?
OpenStudy (anonymous):
so 4/25?
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