Question

Joe and his friends are playing a game w/ 2 dice. Joe must roll a sum of 7 to get points. Jay must roll a sum of 5. Jane must roll a sum of 2, and Jamie a sum of 10. Which friend is more likely to get the most points?

Answer 1

@Kitt020912

Answer 2

Standard Dice:

p(2) = p(12) = 1/36
p(3) = p(11) = 2/36
Can you complete the table?

Answer 3

uhm, let me try

Answer 4

Chinchilla, everyone else is beating me to the answers I'm sorry :l

Answer 5

It's ok:)

Answer 6

Francais, oui?

Answer 7

Could you explain more thoroughly what you want me to do, Tk?

Answer 8

Who has the highest probability?

p(2) = p(12) = 1/36
p(3) = p(11) = 2/36
p(4) = p(10) = 3/36
p(5) = p(9) = 4/36
Can you finsh the table, now?

Answer 9

Lol, vous aimez parler français aussi bien que vous n'avez pas? :D

Answer 10

lol.

Answer 11

Je n'ai toujours pas l'obtenir

Answer 12

Et vous?

Answer 13

En halua puhua ranskaa.

I am not yet asking you to get it. I am asking you to complete the table. If we have the table, we can solve the problem.

Answer 14

Okay.

Answer 15

You speak finnish? :0

Answer 16

anyway.... let me attempt it...again...

Answer 17

p(6) = p(8) = 3/36

like that?

Answer 18

Osaan hiukan.

p(6) = p(8) = 5/36
p(7) = 6/36

Joe must roll a sum of 7 to get points.
Jay must roll a sum of 5.
Jane must roll a sum of 2, and
Jamie a sum of 10.

p(Joe gets a point on a single roll) = 6/36
p(Jay gets a point on a single roll) = 4/36
p(Jane gets a point on a single roll) = 1/36
p(Jamie gets a point o na single roll) = 3/36

Are we yet seeing it?

Answer 19

er, let me read all thet^
one moment

Answer 20

where are you getting the numbers from?

Answer 21

o right, but y are u subtracting one?

Answer 22

Draw a 6x6 grid.

At the top of each column, write the values 1, 2, 3, 4, 5, 6

At the left of each row, write the values 1, 2, 3, 4, 5,6

Fill in the grid with the values obtained by adding the corresponding column header and row header.

See if your grid looks like a good representation of what you would get by rolling two standard dice.

Count the 2s in the grid.
Count the 3s in the grid.
Count the 4s in the grid.
...
Count the 11s in the grid.
Count the 12s in the grid.

Answer 23

one sec

Answer 24

@Kitt020912

Answer 25

s'il vous plaît aidez-moi

Answer 26

hmm. just a sec alright?

Answer 27

ok.

Answer 28

@Firejay5

Answer 29

[kitt: webwhiteboard <--]

Answer 30

Help please.

Answer 31

mitt one moment..

Answer 32

Joe will have the most possibilities

Answer 33

How so?

Answer 34

Well you have to think of it as dice(die)

Answer 35

Okay.

Answer 36

6 sides of a dice

Answer 37

Alright.

Answer 38

And then?

Answer 39

Follow this:
1st dice 2nd dice
1 1
2 2
3 3
4 4
5 5
6 6

Answer 40

Hmmm. Okay.

Answer 41

So Joe would be 6 6 ?

Answer 42

Joe would have the most possibilities

Answer 43

Alright.

Answer 44

Adding number that add to 7: 1 and 6, 5 + 2, and 3 and 4

Answer 45

Ok, thanks!

Answer 46

I have some more.

Answer 47

Joe = 3
Jay = 2
Jane = 1
Jamie = 2

Answer 48

Oooh. Okay.

Answer 49

do you want to know why Jay, Jane, and Jamie aren't it

Answer 50

u have to see how many numbers on a die would add up to each certain number,yes?

Answer 51

yes probability is basically like adding up, but not always

Answer 52

Okay. Why are the others not it?

Answer 53

Jay is sum of 5 right

Answer 54

Yes.

Answer 55

well there's a 2 probability of getting a 5: 3 + 2 and 4 + 1

Answer 56

Ohhhhhh. OKAY!

Answer 57

I think Im understanding.

Answer 58

Jane is a sum of 2: 1 + 1
Jamie is a sum of 10: 5 + 5 and 6 + 4

Answer 59

How old are you and what grade are you in

Answer 60

Ooooh. How many combinations of the certain amount of points.

Answer 61

Why and why?

Answer 62

Anyway, thanks. I'm off to post some more questions. :)

Answer 63

just asking sorry if it's too personal

Answer 64

Oh. Just because?

Answer 65

Well, let me finish posting this question first.

Answer 66

just to see what grade you are learning this in

Answer 67

about 5th - 8th grade