Question

Mike surveyed the students at his school to determine which activity they would like to take part in. The bowling alley offered a 20 percent discount if 300 students of the school's 560 would sign up for the trip. Mike surveyed a random sample and asked which activity they would prefer.

Bowling-60
Skating-90
Attend a play-15
Swimming-35

Based on the data in the survey,how many students are likely to choose bowling?

A. 98
B. 42
C. 168
D. 252


Will they get the discount offered by the bowling alley?

Answer 1

@Firejay5

Answer 2

@tkhunny

Answer 3

@Luis_Rivera

Answer 4

@ash2326

Answer 5

I think it's D. 252, but I am not for sure

Answer 6

How did you get that; do you mind explaining?

Answer 7

I am not that good at Random Samples

Answer 8

Oh, ok. I'll just put 252.

Answer 9

Do you trust me

Answer 10

Will they get the discount offered by the bowling alley?

Answer 11

And yes, sure, I trust you.

Answer 12

They won't

Answer 13

Okay.

Answer 14

because only 60 students want to go

Answer 15

Alright. Thanks!

Answer 16

well wait a second

Answer 17

Okay.

Answer 18

Add each of the answers A, B, C, and D to 6 and see if it equals 300 or close to it

Answer 19

Alright.

Answer 20

560.

Answer 21

252 + 60 = 312 students, so they will have the discount

Answer 22

Oh ok/

Answer 23

Why did you say 560

Answer 24

so they will

Answer 25

I added 98+42+168+252

Answer 26

NVM though.

Answer 27

300 students of the 560 students will get the 20% discount

Answer 28

Ah. So no?

Answer 29

252 + 60 = 312, so yes

Answer 30

Oh. Okay. Thanks!

Answer 31

I believe so Idk

Answer 32

Wow...

Sample Size is 200. This is an amazing 200/560 = 36% of the population.

This gives the following naive proportions that might choose each option.

Bowling-60/200 = 30% ==> 168 / 560
Skating-90/200 = 45% ==> 252 / 560
Attend a play-15/200 = 7.5% ==> 42 / 560
Swimming-35/200 = 17.5% ==> 98 / 560

Checking 168 + 252 + 42 + 98 = 560 -- Good.

Note: This sort of survey and extrapolation is loaded with error potential. I called it "naive" in order to be VERY polite.

Answer 33

@tkhunny It should be 300

Answer 34

Please define "it".

The sample size is 200.
The student body is 560.

Use your naive predictive measure to see if your student body will meet the bowling alley's requirement of 300.

Then asnwer the questions:

1) Based on the data in the survey, how many students are likely to choose bowling?
2) Will they get the discount offered by the bowling alley?

Answer 35

560 is total students and sample size is 300 = 20% discount of students who want to go to the bowling alley

Answer 36

The sample size is NOT 300.

Bowling-60
Skating-90
Attend a play-15
Swimming-35

60 + 90 + 15 + 35 = 200

The sample size is 200.

Answer 37

Okay, what's the answer

Answer 38

It is already given in the discussion above. Please demonstrate your ability to understand the question by selecting the correct responses.

Answer 39

B. 42 then

Answer 40

I had a bad connection;sorry. But it's okay, Jay and Tk. You may now leave my post if you wish to do so:)

Answer 41

why

Answer 42

If you want to attend the play, then 42 is correct. Try the bowling alley, instead.

Answer 43

C. then

Answer 44

Now answer the final question. Is 168 > 300?