Question

use polynomial long divion to divide x^6-64 by x^2+4

Answer 1

first set up the division format , where x^6-64 is in the box and you are trying to see how many times x^2+4 will go into it.

so first take the first term which would be x^2 , how many times does that go into x^6. you do it like you would any normal division problem.

Answer 2

x^3

Answer 3

X^4

Answer 4

okay no multiply x^3 by x^2+4 and put that under the X^6-64
should look like this x^6-64
-(what you get for multiplying x^3 through it)

Answer 5

oops, yeah its x^4 so multiple that by x^2+4 and subtract it under the the x^6-64

Answer 6

make sure to distribute the negative sign though

Answer 7

x^6+4x^4

Answer 8

well -x^6 so that cancels out the x^6

Answer 9

but then what would i do with -64 and +4x^4

Answer 10

okay so now subtract it from x^6-64 so it will be x^6-64
-(x^6+4x^4)

after distributing the negative it looks like this x^6-64
-x^6 - 4x^4

then you are left with -4x^4-64 (repeat process, how many times does x^2+4 go into it)

Answer 11

4x^2

Answer 12

okay repeat the process 4x^2 x the x^2+4 and subtract it from the -4x^4-64

remember to distribute the negative

Answer 13

16x^2+64

Answer 14

no you've made a mistake somewhere along the way , you should be getting 8x^2-64 after you subtract

Answer 15

-4x^2-64
-(-4x^2-8x^2)


becomes -4x^2-64
+ 4x^2 + 8x^2
-----------------------
8x^2-64

Answer 16

i saw the mistake