Who Wants To Be My Partner ?? *fan and medal awarded*
my assignment is collaborative. i dont have a partner. does anyone want to be my partner and help me finish ?
y = ax^3 + bx^2 + cx + d Graph this using any graphing technology of your choice. However, replace the variables a, b, c, and d with numbers. For example, you could graph y = 2x^3 + 3x^2 – x + 2. Observe the graphed outcomes together (or independently if working alone).
haha ight just to let you kno im ranked 3 at pearland high
good for u
first dy/dx= 3ax² +bx + c
1 Sec
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Ok so.
so 3a(-2)² +b(-2) + c = 0
ok
and 3a(2)² +b(2) + c = 0
ok
Now if you substitute -2 in for x and 6 in for y you get another linear equation. 6 = a(-2)³+b(-2)²+c(-2)+d
okay i think u misunderstood.
it doesnt need to be explained to me. its a collaborative assignment. this part is what im supposed to have my partner do. im not supposed to do it. i already done my part.
Oh OK i get you now.
so can u fulfill the partner status ?
Well i would but i cant; i'm currently making a program for a company. An Anti Virus system and iv'e been busy with that. If you want fan me and i will msg you if i have time on my hands?
well if u have the time to explain it im sure u have the time to jus graph it.
i jus need y = 2x^3 + 3x^2 – x + 2 put onto a graph and i can turn it in
Why do you dislike me? I just don't have time to do it.
if u have time to explain it, then u have time to graph it. it would actually take less time to graph it.
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