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Mathematics 9 Online
OpenStudy (anonymous):

Arc Length of a Polar Curve. Please see equation below.

OpenStudy (anonymous):

\[L=\int\limits_{\alpha}^{\beta}\sqrt{r ^{2}+(dr/d \theta) ^{2}} d \theta \] Problem: \[r=a\]

OpenStudy (anonymous):

I know you can just use geometry to figure it out, but I'm required to use The arc length equation above.

OpenStudy (anonymous):

I'm a little confused on the whole "r=a" portion. How am I to take to derivative of that?

OpenStudy (abb0t):

I think that means you have \[a^2\]

OpenStudy (anonymous):

Wouldn't that be for \[r ^{2} \]? Is that also for \[dr/d\] ?

OpenStudy (anonymous):

*dr/d(theta)

OpenStudy (turingtest):

r=a means nothing by itself assuming there is no drawing, I can only guess that this means that r is a constant, and the derivative of a constant is...?

OpenStudy (anonymous):

zero

OpenStudy (turingtest):

and then the integral becomes trivial, yes if there is another interpretation to the problem I think more info is required. what the heck is "a" ?

OpenStudy (anonymous):

There is no drawing. The problem from the text is "The entire circle r=a" That's all that's given. :/

OpenStudy (turingtest):

Then I interpret the problem as I stated above. If you don't disagree with me I think you should try to take it from there.

OpenStudy (anonymous):

I still don't get it... I understand you take the integral but overall I'm just confused

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