Question

Solve e^x - e^-x / 2 = 2

Answer 1

Multiply both sides by e^x. It will be a quadratic equation.

Answer 2

^^

Answer 3

THANKS I WILL TRY!!

Answer 4

What do I do after that?

Answer 5

Help I am STUCK !!!!!!

Answer 6

\[e^x-\frac{1}{2e^x}=2\]

Answer 7

Is that the problem?

Answer 8

I think \[e ^{x}-e ^{-x}\div2=2\] is the question

Answer 9

Well then, that simplifies to:
\[2e ^{2x}-4e ^{x}-1=0\]

Answer 10

Which will not factor.

Answer 11

I solved it boys, thanks a lot for your help! ! :)

Answer 12

Let e^x be u and e^-x be 1/u
Therefore, u-2/u=2
u^2-2=2u
u^2-2u-2=0
We have, \[u=\frac{ -b \pm \sqrt{b ^{2}-4ac} }{ 2a }\]
Now solve it.