Question

Could someone solve y=2x^2/x+1 at x=2 using the chain rule. I keep getting 8/9 as an answer, but its wrong and I don't know what I'm doing wrong.

Answer 1

Is this the equation?
\[y=\frac{2x ^{2}}{x+1}\]

Answer 2

yes

Answer 3

Do you want dy/dx at x = 2 ?

Answer 4

yes

Answer 5

\[if\ y=\frac{u}{v}\ then\ \frac{dy}{dx}=\frac{v\frac{du}{dx}-u\frac{dv}{dx}}{v ^{2}}\]
In your case
\[u=2x ^{2}\]
\[v=x+1\]
Can you carry on with the differentiation?

Answer 6

WAIT!!!!! i know what I was doing wrong. Thank you

Answer 7

Gr8! If you need more help please ask :)

Answer 8

ok thanks

Answer 9

I need help with another question