Question

Help with converting the equation to rectangular form?
cos2Ө=1

Answer 1

whats your progress ? did you try ?

Answer 2

cos2Ө=1
(cos^2Ө)-(sin^2Ө)=1
(using the double angle formula)
But from here, I'm stuck :(

Answer 3

basically you'll need these : \(\cos 2\theta = \cos^2 \theta- \sin^2 \theta\)
then divide both sides by cos^2 theta

Answer 4

then use \(\sec^2\theta = 1+ \tan^2 \theta\)

Answer 5

and lastly, \(\theta = \tan^{-1}\dfrac{y}{x}\)

Answer 6

tell us what u get , so that we can verify your steps...

Answer 7

cos2Ө=1
(cos^2Ө)-(sin^2Ө)=1
1-(tan^2Ө)=(1/cos^2Ө).....divided both sides by (cos^2Ө)
1-(tan^2Ө)=(sec^2Ө)
Is this correct so far?
... sorry I took so long to reply,,
I appreciate you helping me

Answer 8

yes, correct, so far...its ok.
now, (sec^2Ө) = 1+ (tan^2Ө)

Answer 9

I think I made a mistake because I got 1-(tan^2Ө)=(sec^2Ө)
instead of "+" like you wrote

Answer 10

no, you did not make any mistake.
1-(tan^2Ө)=(sec^2Ө)
then since, (sec^2Ө) = 1+ (tan^2Ө) we get
1-(tan^2Ө) = 1+ (tan^2Ө)
isolate (tan^2Ө) from here, and put theta=...

Answer 11

1-(tan^2Ө)=(sec^Ө)
1-(tan^2Ө)=1+(tan^2Ө)
0=2(tan^2Ө)
0=(tan^2Ө)
0=tanӨ
0=y/x
y=0(x)
y=0....final answer

Answer 12

Thank you for taking time to help me,,
I appreciate it!

Answer 13

y=0 is correct, but don't forget to mention that \(x \ne 0\)