Question

Evaluate the integral.

Answer 1

\[\sqrt{1+\sin^{2}x} sinxcosx dx\]

Answer 2

what is the trig id of 1+sin^2x?

Answer 3

sorry \[1+\sin ^{2}x\]

Answer 4

cos^2

Answer 5

is the answer: 1/3(sin^2x+1)^3/2 +c??

Answer 6

sub in cos^2

Answer 7

s^2 + c^2 = 1

c^2 = 1 - s^2

you sure your post is correct?

Answer 8

yup

Answer 9

was my answer correct?

Answer 10

\[cos^2 \ne \sqrt{1+sin^2}\]

Answer 11

is the answer: 1/3(sin^2x+1)^3/2 +c??

Answer 12

not if youve posted your question correctly :/

Answer 13

thats what wolframalpha told me :(

Answer 14

and you dont trust the wolf? cause I was assuming you were subbing in cos for sqrt(1+sin^2)

Answer 15

i let u=sin^2x+1 and du=2sinxcosx

Answer 16

that seems a smart thing to do :)

Answer 17

well thats the answer i got then.