Question

State if it have solution or no solution

4y^2+169=0

Answer 1

Solution in \(\mathbb R\)?

Answer 2

i mean reals?

Answer 3

Yes

Answer 4

Compare your quadratic equation with \(ay^2+by+c=0\)
find \[a=...?\\b=...?\\c=...?\]
if \(b^2-4ac \ge 0\), then it has a solution,
if \(b^2-4ac <0\)
then no solution

Answer 5

because square root of negative numbers are not defined in reals...

Answer 6

It has no solition?

Answer 7

Solution*

Answer 8

that would be correct.
just curious....what did you get for a,b,c ??

Answer 9

a=4 b=0 c=169?

Answer 10

thats correct! good work then :)

Answer 11

Thanks!

Answer 12

welcome ^_^